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x^2-3.25=9
We move all terms to the left:
x^2-3.25-(9)=0
We add all the numbers together, and all the variables
x^2-12.25=0
a = 1; b = 0; c = -12.25;
Δ = b2-4ac
Δ = 02-4·1·(-12.25)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-7}{2*1}=\frac{-7}{2} =-3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+7}{2*1}=\frac{7}{2} =3+1/2 $
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